5b^2-28b-12=0

Solution for 5b^2-28b-12=0 equation:

Simplifying
5b2 + -28b + -12 = 0

Reorder the terms:
-12 + -28b + 5b2 = 0

Solving
-12 + -28b + 5b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-2 + -5b)(6 + -1b) = 0

Subproblem 1
Set the factor '(-2 + -5b)' equal to zero and attempt to solve:

Simplifying
-2 + -5b = 0

Solving
-2 + -5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -5b = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -5b = 0 + 2
-5b = 0 + 2

Combine like terms: 0 + 2 = 2
-5b = 2

Divide each side by '-5'.
b = -0.4

Simplifying
b = -0.4
Subproblem 2
Set the factor '(6 + -1b)' equal to zero and attempt to solve:

Simplifying
6 + -1b = 0

Solving
6 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1b = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1b = 0 + -6
-1b = 0 + -6

Combine like terms: 0 + -6 = -6
-1b = -6

Divide each side by '-1'.
b = 6

Simplifying
b = 6
Solution
b = {-0.4, 6}